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SERVICE FACTOR GUIDE
 
 

MATERIALS OF CONSTRUCTION

TYPES & SIZES

MATERIALS

S-50,70

Sl / Al

♦ S,SR,SE,SRE( hubs only ),K,KR, SN, SEN, KN

Cl

♦ S-50,70 & SRE ( spacers only )

Al

♦ Retainer rings

MS

♦ Star / Spider / Strip / Snaps / Pads

Nitrite Rubber

♦ Screws / Bolts

MS / HT



TYPE OF LOAD

EXAMPLE OF LOAD

ELECTRIC MOTORS STEAM TURBINES

DIESEL ENGINES GASOLINE ENGINES

6 OR MORE CYL.

LESS THAN 6 CYL.

Light duty Or Uniform load

Generators ( uniform load ). Centrifugal pumps. Agitators ( light duty ). Compressors ( centrifugal ). Belt Conveyors ( Uniform load ). Feeders ( uniform load )

1.00

1.50

2.00

Medium duty or pulsating and varying loads without severe shocks

Generators ( varying load ). Reciprocating pumps. Mixers and pulverizers ( light ). Cranes & hoists ( varying heavy loads ) Conveyors ( varying heavy loads )

1.50

2.00

2.50

Heavy duty or severe shock loads High vibrations

Compressors ( reciprocating ). Crushers & Pulverizers ( heavy duty ), Hammer mills ( heavy duty ) Vibrating Screens

2.00

2.50

3.00

 

SELECTION PROCEDURE

Data required :

A. Power in HP
B. Speed in rpm
C. Shaft size of driver & driven in mm
D. Service factor (per guide)

  • Determine the 'SERVICE FACTOR' from guide chart given.
  • Multiply the service factor to the H.P. of the driver (eg. electric motor) to obtain the 'EFFECTIVE H.P.'
  • Refer the 'HP rpm' chart in 'TABLE T. Taking the appropriate rpm column, scroll down the column until the HP equal to or greater than the effective HP is located.
  • Ensure that the shaft sizes of your equipments are within pilot & max. bore sizes indicated in the same 'TABLE T .
  • If the shaft size are larger than the max. bore indicated, select from the next higher sizes of couplings where the shaft size is accommodated.
  • Thus the size of the coupling can be determined. The ' Type' of the coupling is at the discretion of the customer.
  • For rpm other than indicated, the effective HP can be determined by simple linear equation.
 

EXAMPLE

A) A coupling is to be selected to couple a centrifugal pump & an electric motor.

The Data is as below -

Power: 25 HP Speed : 1500 rpm
Shaft sizes : Pump 28mm,                                Motor 48mm
  • From the 'SERVICE FACTOR GUIDE', the S.F. is 1.00. Thus, the effective HP is 25x1.00 = 25HP
  • From the Table 1, scrolling down the column of 1500 rpm, 25.5HP is located which determines the smallest
    size of coupling which can transmit power of 25HP.
  • This coupling can take max shaft size of 48mm as required.
  • Thus, the size of coupling is '150'

B) If the shaft size in above application was say 55mm, size 190 coupling shall be appropriate.

NOTES

  • The angular shaft displacement should not exceed 1.5 deg. and parallel 0.38 mm for avoiding early failure of couplings.
  • While fitting couplings care should be taken so that the gap between jaw and body is maintained.
  • Couplings will be supplied with finish bore and keyway against specific requirements at extra cost.

    For further details please contact us.

FORMULAE

1 H.P. 0.75 kw.
1 inch                 = 25.4 mm.
Torque (kg-m)    =
HP x 716
rpm
 
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